20 lines
340 B
Plaintext
20 lines
340 B
Plaintext
CONST limite = 10000
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DIM Q(limite)
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Q(1) = 1
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Q(2) = 1
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cont = 0
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FOR i = 3 TO limite
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Q(i) = Q(i - Q(i - 1)) + Q(i - Q(i - 2))
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IF Q(i) < Q(i-1) THEN cont = cont + 1
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NEXT i
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PRINT "First 10 terms: ";
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FOR i = 1 TO 10
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PRINT Q(i); " ";
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NEXT i
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PRINT
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PRINT "Term 1000: "; Q(1000)
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PRINT "Terms less than preceding in first 100k: "; cont
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