CONST limite = 10000
DIM Q(limite)
Q(1) = 1
Q(2) = 1

cont = 0
FOR i = 3 TO limite
    Q(i) = Q(i - Q(i - 1)) + Q(i - Q(i - 2))
    IF Q(i) < Q(i-1) THEN cont = cont + 1
NEXT i

PRINT "First 10 terms: ";
FOR i = 1 TO 10
    PRINT Q(i); " ";
NEXT i

PRINT
PRINT "Term 1000: "; Q(1000)
PRINT "Terms less than preceding in first 100k: "; cont