18 lines
353 B
JavaScript
18 lines
353 B
JavaScript
function range(begin, end) {
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for (let i = begin; i < end; ++i)
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yield i;
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}
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function triples(n) {
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return [
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[x, y, z]
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for each(x in range(1, n + 1))
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for each(y in range(x, n + 1))
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for each(z in range(y, n + 1))
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if (x * x + y * y == z * z)
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]
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}
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for each(var triple in triples(20))
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print(triple);
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