14 lines
486 B
Python
14 lines
486 B
Python
from collections import Counter
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def function_length_frequency(func, hrange):
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return Counter(len(func(n)) for n in hrange).most_common()
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if __name__ == '__main__':
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from executable_hailstone_library import hailstone
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upto = 100000
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hlen, freq = function_length_frequency(hailstone, range(1, upto))[0]
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print("The length of hailstone sequence that is most common for\n"
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"hailstone(n) where 1<=n<%i, is %i. It occurs %i times."
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% (upto, hlen, freq))
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