RosettaCodeData/Task/Zebra-puzzle/Python/zebra-puzzle-1.py

74 lines
2.8 KiB
Python

from logpy import *
from logpy.core import lall
import time
def lefto(q, p, list):
# give me q such that q is left of p in list
# zip(list, list[1:]) gives a list of 2-tuples of neighboring combinations
# which can then be pattern-matched against the query
return membero((q,p), zip(list, list[1:]))
def nexto(q, p, list):
# give me q such that q is next to p in list
# match lefto(q, p) OR lefto(p, q)
# requirement of vector args instead of tuples doesn't seem to be documented
return conde([lefto(q, p, list)], [lefto(p, q, list)])
houses = var()
zebraRules = lall(
# there are 5 houses
(eq, (var(), var(), var(), var(), var()), houses),
# the Englishman's house is red
(membero, ('Englishman', var(), var(), var(), 'red'), houses),
# the Swede has a dog
(membero, ('Swede', var(), var(), 'dog', var()), houses),
# the Dane drinks tea
(membero, ('Dane', var(), 'tea', var(), var()), houses),
# the Green house is left of the White house
(lefto, (var(), var(), var(), var(), 'green'),
(var(), var(), var(), var(), 'white'), houses),
# coffee is the drink of the green house
(membero, (var(), var(), 'coffee', var(), 'green'), houses),
# the Pall Mall smoker has birds
(membero, (var(), 'Pall Mall', var(), 'birds', var()), houses),
# the yellow house smokes Dunhills
(membero, (var(), 'Dunhill', var(), var(), 'yellow'), houses),
# the middle house drinks milk
(eq, (var(), var(), (var(), var(), 'milk', var(), var()), var(), var()), houses),
# the Norwegian is the first house
(eq, (('Norwegian', var(), var(), var(), var()), var(), var(), var(), var()), houses),
# the Blend smoker is in the house next to the house with cats
(nexto, (var(), 'Blend', var(), var(), var()),
(var(), var(), var(), 'cats', var()), houses),
# the Dunhill smoker is next to the house where they have a horse
(nexto, (var(), 'Dunhill', var(), var(), var()),
(var(), var(), var(), 'horse', var()), houses),
# the Blue Master smoker drinks beer
(membero, (var(), 'Blue Master', 'beer', var(), var()), houses),
# the German smokes Prince
(membero, ('German', 'Prince', var(), var(), var()), houses),
# the Norwegian is next to the blue house
(nexto, ('Norwegian', var(), var(), var(), var()),
(var(), var(), var(), var(), 'blue'), houses),
# the house next to the Blend smoker drinks water
(nexto, (var(), 'Blend', var(), var(), var()),
(var(), var(), 'water', var(), var()), houses),
# one of the houses has a zebra--but whose?
(membero, (var(), var(), var(), 'zebra', var()), houses)
)
t0 = time.time()
solutions = run(0, houses, zebraRules)
t1 = time.time()
dur = t1-t0
count = len(solutions)
zebraOwner = [house for house in solutions[0] if 'zebra' in house][0][0]
print "%i solutions in %.2f seconds" % (count, dur)
print "The %s is the owner of the zebra" % zebraOwner
print "Here are all the houses:"
for line in solutions[0]:
print str(line)