20 lines
488 B
Plaintext
20 lines
488 B
Plaintext
var s = [1, 2, 2, 3, 4, 4, 5]
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// There is no output as 'prev' is created anew each time
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// around the loop and set implicitly to null.
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for (i in 0...s.count) {
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var curr = s[i]
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var prev
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if (i > 0 && curr == prev) System.print(i)
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prev = curr
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}
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// Now 'prev' is created only once and reassigned
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// each time around the loop producing the desired output.
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var prev
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for (i in 0...s.count) {
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var curr = s[i]
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if (i > 0 && curr == prev) System.print(i)
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prev = curr
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}
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