RosettaCodeData/Task/Van-Eck-sequence/EasyLang/van-eck-sequence.easy

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len arr[] 1000
for n to 1000 - 1
for m = n - 1 downto 1
if arr[m] = arr[n]
arr[n + 1] = n - m
break 1
.
.
.
for i to 10
write arr[i] & " "
.
print ""
for i = 991 to 1000
write arr[i] & " "
.