RosettaCodeData/Task/Zeckendorf-arithmetic/C++/zeckendorf-arithmetic-1.cpp

73 lines
2.4 KiB
C++

// For a class N which implements Zeckendorf numbers:
// I define an increment operation ++()
// I define a comparison operation <=(other N)
// I define an addition operation +=(other N)
// I define a subtraction operation -=(other N)
// Nigel Galloway October 28th., 2012
#include <iostream>
enum class zd {N00,N01,N10,N11};
class N {
private:
int dVal = 0, dLen;
void _a(int i) {
for (;; i++) {
if (dLen < i) dLen = i;
switch ((zd)((dVal >> (i*2)) & 3)) {
case zd::N00: case zd::N01: return;
case zd::N10: if (((dVal >> ((i+1)*2)) & 1) != 1) return;
dVal += (1 << (i*2+1)); return;
case zd::N11: dVal &= ~(3 << (i*2)); _b((i+1)*2);
}}}
void _b(int pos) {
if (pos == 0) {++*this; return;}
if (((dVal >> pos) & 1) == 0) {
dVal += 1 << pos;
_a(pos/2);
if (pos > 1) _a((pos/2)-1);
} else {
dVal &= ~(1 << pos);
_b(pos + 1);
_b(pos - ((pos > 1)? 2:1));
}}
void _c(int pos) {
if (((dVal >> pos) & 1) == 1) {dVal &= ~(1 << pos); return;}
_c(pos + 1);
if (pos > 0) _b(pos - 1); else ++*this;
return;
}
public:
N(char const* x = "0") {
int i = 0, q = 1;
for (; x[i] > 0; i++);
for (dLen = --i/2; i >= 0; i--) {dVal+=(x[i]-48)*q; q*=2;
}}
const N& operator++() {dVal += 1; _a(0); return *this;}
const N& operator+=(const N& other) {
for (int GN = 0; GN < (other.dLen + 1) * 2; GN++) if ((other.dVal >> GN) & 1 == 1) _b(GN);
return *this;
}
const N& operator-=(const N& other) {
for (int GN = 0; GN < (other.dLen + 1) * 2; GN++) if ((other.dVal >> GN) & 1 == 1) _c(GN);
for (;((dVal >> dLen*2) & 3) == 0 or dLen == 0; dLen--);
return *this;
}
const N& operator*=(const N& other) {
N Na = other, Nb = other, Nt, Nr;
for (int i = 0; i <= (dLen + 1) * 2; i++) {
if (((dVal >> i) & 1) > 0) Nr += Nb;
Nt = Nb; Nb += Na; Na = Nt;
}
return *this = Nr;
}
const bool operator<=(const N& other) const {return dVal <= other.dVal;}
friend std::ostream& operator<<(std::ostream&, const N&);
};
N operator "" N(char const* x) {return N(x);}
std::ostream &operator<<(std::ostream &os, const N &G) {
const static std::string dig[] {"00","01","10"}, dig1[] {"","1","10"};
if (G.dVal == 0) return os << "0";
os << dig1[(G.dVal >> (G.dLen*2)) & 3];
for (int i = G.dLen-1; i >= 0; i--) os << dig[(G.dVal >> (i*2)) & 3];
return os;
}