func nthroot(n, a, precision=1e-5) {
var x = 1.float
var prev = 0.float
while ((prev-x).abs > precision) {
prev = x;
x = (((n-1)*prev + a/(prev**(n-1))) / n)
}
return x
say nthroot(5, 34) # => 2.024397458501034082599817835297912829678314204