25 lines
1.9 KiB
Plaintext
25 lines
1.9 KiB
Plaintext
Given two sets of items then if any item is common to any set then the result of applying ''consolidation'' to those sets is a set of sets whose contents is:
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* The two input sets if no common item exists between the two input sets of items.
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* The single set that is the union of the two input sets if they share a common item.
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<br>Given N sets of items where N>2 then the result is the same as repeatedly replacing all combinations of two sets by their consolidation until no further consolidation between set pairs is possible.
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If N<2 then consolidation has no strict meaning and the input can be returned.
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;'''Example 1:'''
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:Given the two sets <tt>{A,B}</tt> and <tt>{C,D}</tt> then there is no common element between the sets and the result is the same as the input.
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;'''Example 2:'''
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:Given the two sets <tt>{A,B}</tt> and <tt>{B,D}</tt> then there is a common element <tt>B</tt> between the sets and the result is the single set <tt>{B,D,A}</tt>. (Note that order of items in a set is immaterial: <tt>{A,B,D}</tt> is the same as <tt>{B,D,A}</tt> and <tt>{D,A,B}</tt>, etc).
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;'''Example 3:'''
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:Given the three sets <tt>{A,B}</tt> and <tt>{C,D}</tt> and <tt>{D,B}</tt> then there is no common element between the sets <tt>{A,B}</tt> and <tt>{C,D}</tt> but the sets <tt>{A,B}</tt> and <tt>{D,B}</tt> do share a common element that consolidates to produce the result <tt>{B,D,A}</tt>. On examining this result with the remaining set, <tt>{C,D}</tt>, they share a common element and so consolidate to the final output of the single set <tt>{A,B,C,D}</tt>
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;'''Example 4:'''
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:The consolidation of the five sets:
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::<tt>{H,I,K}</tt>, <tt>{A,B}</tt>, <tt>{C,D}</tt>, <tt>{D,B}</tt>, and <tt>{F,G,H}</tt>
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:Is the two sets:
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::<tt>{A, C, B, D}</tt>, and <tt>{G, F, I, H, K}</tt>
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<br>
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'''See also'''
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* [[wp:Connected component (graph theory)|Connected component (graph theory)]]
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* [[Range consolidation]]
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<br><br>
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