RosettaCodeData/Task/Permutations-by-swapping/Python/permutations-by-swapping-3.py

18 lines
574 B
Python

def s_permutations(seq):
items = [[]]
for j in seq:
new_items = []
for i, item in enumerate(items):
if i % 2:
# step up
new_items += [item[:i] + [j] + item[i:]
for i in range(len(item) + 1)]
else:
# step down
new_items += [item[:i] + [j] + item[i:]
for i in range(len(item), -1, -1)]
items = new_items
return [(tuple(item), -1 if i % 2 else 1)
for i, item in enumerate(items)]