RosettaCodeData/Task/Non-continuous-subsequences/EasyLang/non-continuous-subsequences...

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func[][] ncsub seq[] s .
if len seq[] = 0
if s >= 3
return [ [ ] ]
.
return [ ]
.
last = seq[$]
len seq[] -1
res[][] = ncsub seq[] (s + s mod 2)
r[][] = ncsub seq[] (s + 1 - s mod 2)
for i to len r[][]
r[i][] &= last
res[][] &= r[i][]
.
return res[][]
.
print ncsub [ 1 2 3 4 ] 0