RosettaCodeData/Task/Burrows-Wheeler-transform/Python/burrows-wheeler-transform.py

17 lines
876 B
Python

def bwt(s):
"""Apply Burrows-Wheeler transform to input string."""
assert "\002" not in s and "\003" not in s, "Input string cannot contain STX and ETX characters"
s = "\002" + s + "\003" # Add start and end of text marker
table = sorted(s[i:] + s[:i] for i in range(len(s))) # Table of rotations of string
last_column = [row[-1:] for row in table] # Last characters of each row
return "".join(last_column) # Convert list of characters into string
def ibwt(r):
"""Apply inverse Burrows-Wheeler transform."""
table = [""] * len(r) # Make empty table
for i in range(len(r)):
table = sorted(r[i] + table[i] for i in range(len(r))) # Add a column of r
s = [row for row in table if row.endswith("\003")][0] # Find the correct row (ending in ETX)
return s.rstrip("\003").strip("\002") # Get rid of start and end markers