from datetime import timedelta, date

DAY     = timedelta(days=1)
START, STOP = date(1900, 1, 1), date(2101, 1, 1)
WEEKEND = {6, 5, 4}     # Sunday is day 6
FMT     = '%Y %m(%B)'

def fiveweekendspermonth(start=START, stop=STOP):
    'Compute months with five weekends between dates'

    when = start
    lastmonth = weekenddays = 0
    fiveweekends = []
    while when < stop:
        year, mon, _mday, _h, _m, _s, wday, _yday, _isdst = when.timetuple()
        if mon != lastmonth:
            if weekenddays >= 15:
                fiveweekends.append(when - DAY)
            weekenddays = 0
            lastmonth = mon
        if wday in WEEKEND:
            weekenddays += 1
        when += DAY
    return fiveweekends

dates = fiveweekendspermonth()
indent = '  '
print('There are %s months of which the first and last five are:' % len(dates))
print(indent +('\n'+indent).join(d.strftime(FMT) for d in dates[:5]))
print(indent +'...')
print(indent +('\n'+indent).join(d.strftime(FMT) for d in dates[-5:]))

print('\nThere are %i years in the range that do not have months with five weekends'
      % len(set(range(START.year, STOP.year)) - {d.year for d in dates}))