F reps(text)
   R (1 .< 1 + text.len I/ 2).filter(x -> @text.starts_with(@text[x..])).map(x -> @text[0 .< x])

V matchstr =
|‘1001110011
  1110111011
  0010010010
  1010101010
  1111111111
  0100101101
  0100100
  101
  11
  00
  1’

L(line) matchstr.split("\n")
   print(‘'#.' has reps #.’.format(line, reps(line)))