fn binarySearchIterative arr value =
(
    lower = 1
    upper = arr.count
    while lower <= upper do
    (
        mid = (lower + upper) / 2
        if arr[mid] > value then
        (
            upper = mid - 1
        )
        else if arr[mid] < value then
        (
            lower = mid + 1
        )
        else
        (
            return mid
        )
    )
    -1
)

arr = #(1, 3, 4, 5, 6, 7, 8, 9, 10)
result = binarySearchIterative arr 6